t(2t+3)+20=2t(t^2-3)

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Solution for t(2t+3)+20=2t(t^2-3) equation: 


Simplifying
t(2t + 3) + 20 = 2t(t2 + -3)

Reorder the terms:
t(3 + 2t) + 20 = 2t(t2 + -3)
(3 * t + 2t * t) + 20 = 2t(t2 + -3)
(3t + 2t2) + 20 = 2t(t2 + -3)

Reorder the terms:
20 + 3t + 2t2 = 2t(t2 + -3)

Reorder the terms:
20 + 3t + 2t2 = 2t(-3 + t2)
20 + 3t + 2t2 = (-3 * 2t + t2 * 2t)
20 + 3t + 2t2 = (-6t + 2t3)

Solving
20 + 3t + 2t2 = -6t + 2t3

Solving for variable 't'.

Reorder the terms:
20 + 3t + 6t + 2t2 + -2t3 = -6t + 2t3 + 6t + -2t3

Combine like terms: 3t + 6t = 9t
20 + 9t + 2t2 + -2t3 = -6t + 2t3 + 6t + -2t3

Reorder the terms:
20 + 9t + 2t2 + -2t3 = -6t + 6t + 2t3 + -2t3

Combine like terms: -6t + 6t = 0
20 + 9t + 2t2 + -2t3 = 0 + 2t3 + -2t3
20 + 9t + 2t2 + -2t3 = 2t3 + -2t3

Combine like terms: 2t3 + -2t3 = 0
20 + 9t + 2t2 + -2t3 = 0

The solution to this equation could not be determined.

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